What will be the speed of a
businessman km/h if it moves with
speed of 20 m/s
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Answered by
0
Answer:
a=v−uta=v−ut
s=ut+12at2s=ut+12at2
v2=u2+2asv2=u2+2as
Let’s calculate the acceleration first, so that we can use (2)
a=v−ut=60–204=10m/s2a=v−ut=60–204=10m/s2
Next, we face a trap in the question. The third second refers to the period of time between t=2t=2 and t=3t=3. (The first second is between t=0t=0 and t=1t=1.)
s2=(20)(2)+12(10)(2)2=60ms2=(20)(2)+12(10)(2)2=60m
s3=(20)(3)+12(10)(3)2=105ms3=(20)(3)+12(10)(3)2=105m
Distance travelled in 3rd second = 105 - 60 = 45m
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