Question

What will be the stopping distance if the initial velocity is doubled?

Answer 1

If the initial velocity is doubled, Then the stopping distance become 4 times.
From the third equation,
v^2=u^2-2as
u^2= v^2+2as
From this equation distance (s) is directly proportional to u^2.

Answer 2

Answer:

The stopping distance will be 4 times.

Explanation:

From the equation of motion, we can deduce that,

s = $\frac{u^2}{2g}$

where g is the acceleration due to gravity

u is the initial velocity

and, s is the distance.

From this equation we can see that s is directly proportional to the square of initial velocity.

According to question, u is doubled so the distance will automatically increase to 4 times as deciphered above.

Thus the stopping distance will increase by 4 times.

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