What will be the sum of Fib ( 1 ) + Fib ( 2 ) + _____ Fib ( 10 ) ? Please, give me correct answer with solution
Answers
Step-by-step explanation:
Here is a longer list: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, ...
Fib (1) + Fib(2) + + Fib(10) = Fib(12) - 1 = 143
Given :
Fib(n) be the nth term of the Fibonacci sequence, with Fib(1)=1,Fib(2)=1,Fib(3)=2
To Find :
Fib (1) + Fib(2) + ... + Fib(10)
Solution:
Fibonacci
a₁ = 1
a₂ = 1
aₙ = aₙ₋₁ + aₙ₋₂
1 , 1 , 2, 3, 5, 8, 13, 21 , 34, 55 , 89 , 144 and so on
Sum of 1st two terms = 1 + 1 = 2 = 3 - 1 = Fourth term - 1
Sum of 1st three terms = 1 + 1 + 2 = 4 = 5 - 1 = Fifth term - 1
Sum of 1st four terms = 1 + 1 + 2 + 3= 7 = 8 - 1 = Sixth term - 1
Hence
Sum of 1st n terms = (n + 2)th term - 1
Sum of 1st 10 terms = (10 + 2)th term - 1
=>Sum of 1st 10 terms =12th term - 1
Fib (1) + Fib(2) + + Fib(10) = Fib(12) - 1
= 144 - 1
= 143
Fib (1) + Fib(2) + + Fib(10) = Fib(12) - 1 = 143
Verification :
1 +1+ 2+ 3+ 5+8+ 13+ 21+ 34+ 55 = 143
Learn More:
Fibonacci अनुक्रम निम्नलिखित रूप में परिभाषित है
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