Physics, asked by parv01mahajan, 1 month ago

what will be the time period of a simple pendulum if the pendulum is taken to a place where the value of g is 4 times that on the surface of the earth?​

Answers

Answered by nitinpranavsavanth
1

Explanation:

Acceleration due to gravity on the surface of the moon is

6

1

that of surface of the earth.

∴g

m

=

6

1

g

e

On earth, T

e

=2π

g

e

L

On Moon, T

m

=2π

g

m

L

T

e

T

m

=

g

m

g

e

=

6

T

m

=

6

T

e

=

6

×4s=10s

Answered by madhumipsc4812
1
A pendulum is a weight suspended from a pivot so that it can swing freely. When a pendulum is displaced sideways from its resting, equilibrium position, it is subject to a restoring force due to gravity that will accelerate it back toward the equilibrium position.
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