Question

What will be the time period of oscillation if the length of second pendulum is one-third

Answer 1

The time period of oscillation if the length of second pendulum is one-third is

$\frac{2}{\sqrt{3} } s$

1. The time period of pendulum is given by
2. $T=2\pi \sqrt{\frac{l}{g} }$ here l is the length of the pendulum and g is acceleration due to gravity
3. T is proportional to  $l^{1/2}$
4. the time period of the second pendulum is 2s
5. Now time period of oscillation if the length of second pendulum is one-third is
6. $\frac{T2}{T1} =\sqrt{\frac{(1/3)l}{l} }$  ,${T2}=2\sqrt{\frac{1}{3} }=\frac{2}{\sqrt{3} }$

Answer 2

Answer:

2/√3

Explanation:

l = 1/3

T is directly proportional to √L ---------eqn 1

So

T' =√L/√3 = T /3 ------ from eqn 1

As time period of simple pendulum is 2 second so plece 2 on the side of T

therefore,

T =2/√3 Answer