Question

What will be the total resistance of the circuit if four resistance of 2 ohm are connected in a series?​

Answer 1

Answer:

Given:

r1 = r2 =r3 = r4 = 2 ohm

Req in series = r1+r2+r3+r4

=4×r

=8 ohm ans

Answer 2

Answer:

The total resistance of the circuit will be $8ohm$

Explanation:

• The obstruction to current flow in an electrical circuit is measured by resistance.
• The Greek letter omega (Ω) represents the unit of measurement for resistance. International System of Units of resistance is ohms.
• The resistance was discovered by Georg Simon Ohm (1784–1854), a German physicist who investigated the connection between voltage, current, and resistance.
• The resistance acts as a gauge to quantify how easily current will flow through a circuit. When resistance falls, current rises, and when resistance rises, current falls.
• Current rises when resistance falls, and it reduces when resistance rises. Resistors are required in order to ensure that current passes at the correct level in circuits.

$Given:r_{1} = r_{2} =r_{3} = r_{4} = 2 ohm\\Req in series = r_{1}+r_{2}+r_{3}+r_{4}\\=4*r\\=8 ohm$

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https://brainly.in/question/1151879

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