Question

What will be the unit digit of the cube root of a number ends with 3?​

Answer 1

Step-by-step explanation:

Let the number be n3=(10×n)+3 where n and 3 are digit (not in multiplication)

$n =( 10 {}^{x} \times a ) +( {10}^{x - 1} \times b)......(10 {}^{0} \times c)$

cube of 10n+3=

$( {10n + 3)}^{3} \\ =( 10n ){}^{3} + 3(10n)(3)(10n + 3) + (3) {}^{3} \\ = 1000 {n}^{3} + 1170n {}^{2} + 27 \\ if \: n = 0 \\ then \: unit \: number \: 7 \\ if \: n = 1 \\ then \: unit \: number \: = 7 \\ if \: n = 2 \\ then \: unit \: number \: = 7 \\ in \: all \: case \: unit \: digit \: is \: always \: 7 \\ so \: 7 \: is \: your \: answer$

plz mark me as BRAINLIEST