Question

what will be the unit digit of the square of the following numbers(i)39 (ii) 297 (i)5125 (iv)7286 (v)8742​

Answer 1

Answer:

i)1(9×9=81)

ii) 9(7×7=49)

iii) 5(5×5=45)

iv)6(6×6=36)

v) 4(2×2=4)

Answer 2

Answer:

the last digits will be

i) 1

ii) 9

iii) 5

iv) 6

v) 4

Step-by-step explanation:

its because the last digit of the square of a number depends upon the last digit of the number given, whose square is to be found.

eg. here 39 ends with 9

and the square of 9 is 81, so the last digit of the squares of 9 and 39 will be the same , that is, 1

rest of them can be solved in the same way