Question

What will be the value of 5 and 15 home equivalent resistance in class cooperatives and parallel cooperatives​

Answer 1

Answer:

Correct option is

D

R/n

2

As we know R∝l(length of wire)

and we are cutting the wire into n equal parts, so each new formed wire's resistor

⇒R

1

=R

2

=R

3

=R

4

=R

5

=...R

n

=

n

R

as the diagram shows, we are connecting them in parallel series then equivalent resistance of combination is given by R

eq

⇒

R

eq

1

=

R

1

1

+

R

2

1

+

R

3

1

+

R

4

1

+...+

R

n

1

⇒

R

eq

1

=

R

n

+

R

n

+

R

n

+...+

R

n

(n times)

⇒

R

eq

1

=(

R

n

)×n

⇒R

eq

=

n

2

R

correct option will be (D)