what will be the value of a and b if :√5+3/√5+7 =a-b √5
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Answer:
Step-by-step explanation:
Given
3+5–√3−5–√=a+b5–√
Take the conjugate of the denominator term and multiply both numerator and denominator by that conjugate.
Here, conjugate of 3−5–√ is 3+5–√ .
Now,
(3+5–√3−5–√)×(3+5–√3+5–√)=a+b5–√
⟹(3+5–√)2(3−5–√)(3+5–√)=a+b5–√
We know
(a+b)2=a2+b2+2ab⋯(1)
(a+b)(a−b)=a2−b2⋯(2)
Apply formula (1) in the numerator and formula (2) in the denominator.
(3)2+(5–√)2+2×3×5–√32−(5–√)2=a+b5–√
9+5+65–√9−5=a+b5–√
⟹14+65–√4=a+b5–√
Take 2 as common from the numerator.
2(7+35–√)4=a+b5–√
⟹7+35–√2=a+b5–√
⟹72+325–√=a+b5–√
Comparing the corresponding rational and irrational parts on both sides, we get:
a=72,b=32
or
a=3.5,b=1.5
Anushreeshukla122:
thank you...
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