Question

What will be the value of constant in the given expression (a - 1)(a - 22(a +3)(a - 4)(a 5)(-6)?​

Answer 1

Answer:

$(a - 1)(a - 22(a +3)(a - 4)(a 5)(-6)$

Answer 2

Concept introduction:

A constant value is a type of value which doesn't change over time or it can be said as a fixed value.

Given:

Here the equation is $(a-1)(a-22)(a+3)(a-4)(a5)(-6)$.

To Find:

We have to find the constant value of that equation.

Solution:

According to the question,

$(a-1)(a-22)(a+3)(a-4)(a5)(-6)\\=-30a(a^{2}-23a +22)(a^{2} -a-12)\\=(-30a^{3} +690a^{2} -660a)(a^{2} -a-12)$

As we can see there is no kind of value without $a$ and $a$ is our integer value so there will be no constant value in this expression.