Question

What will be the value of current (in

a.In a 50 cm long air-core solenoid, if the value of magnetic field at the center of the solenoid is 5 mt and the solenoid has 300 turns?

Answer 1

Answer:

According to my calculations, the value of the current will be about 6.66 A (recurring decimal alert) (also used approximation). Please make sure to get it verified by a teacher.

Answer 2

Solenoid

Number of turns in solenoid $=300$

Length of solenoid $= 50 \ cm$

Magnetic field $= 5 \ mT$

As we know that,

$B=\frac{\mu_0IN}{L}$

where,

N is number of turns in solenoid

I is current in the coil

L is the length of the coil

$\implies 5\times 10^{-3}=\frac{4\pi\times 10^{-7}\times 300\times I}{50\times 10^{-2}}$

$\implies I = 6.63\ A$

Hence, the value of current is 6.63 A.