Question

What will be the value of electric field at the centre of electric dipole?

Answer 1

this is how i have done

Explanation:

Answer 2

Given:

An electric dipole with charges +Q and -Q

Distance between the charges =2a

O is the center of the dipole

To find:

EF at O

Solution:

We know that the electric field produced by a charge Q at a point P, y distance away = kQ/y²

where k is the Coulomb's constant and is equal to 9 X 10⁹ kg m³ s⁻² C⁻²

The direction of EF is from positive to negative charge.

Electric field due to +Q charge at center O is given by E 1 = kQ/a²

Electric field due to -Q charge at center O is given by E 2 = kQ/a²

Since, both E1  and E2  are in the same direction the resultant Electric Field = E = kQ/a² + kQ/a²

= 2 (kQ/a²)

Hence, the value of the electric field at the center of an electric dipole is 2 (kQ/a²)