Question

What will be the value of β for a solid for which α has a value of 2 x 10-5 K-1 :

Answer 1

Answer ✨⤵️

hope it helps

Here by using relation between coefficient of linear expansion and coefficient of cubical expansion, we get

r=3α

α (linear coefficient of expansion)

=31r (coefficient of cubical expansion)

=31×5.1×10−5

=1.7×10−5per C

Answer 2

Answer:

Required value is

$\beta = 4 \times {10}^{ - 5} /°C$

Explanation:

Given value of α for a solid is

$2 \times {10}^{ - 5} {k}^{ - 1}$

Here

$\alpha = linear \: expansion$

We have to found value of superficial expansion.

We know that,

$6 \alpha = 3 \beta = 2 \gamma$

Now,

$6 \times 2 \times {10}^{ - 5} = 3 \times \beta$

$\beta = \frac{6 \times 2 \times {10}^{ - 5} }{3} = 2 \times 2 \times {10}^{ - 5} = 4 \times {10}^{ - 5} /°C$

Therefore required answer is

$\beta = 4 \times {10}^{ - 5} /°C$