Question

What will be the value of j=--k+2k+(l=k,l++) if k is 20 initially​

Answer 1

answer: 77

explanation:

° Here , k is equal to 20

Therefore --k will be 19 it is a

prefix decrement operator that's why the value will first change

then used.

°Given ( l ) is equal to( k) here this means that ( l ) value is equal to

( k ) that is 20 initially and then second condition is it has postfix

increment operator l++ therefore its value will first used then changed that is it will be used as 20 .

°Then 2k is equal to 19 * 2 ==38

( here k value will change because k is decremented in first operand ).

Now solving ,

j = --k + 2k + l++ ( l is 20 as mentioned above)

j = 19 + 38 + 20

j = 77

[note:]

{1}

j value will not change to 78 but ( I )value will now change into 21 after execution .

{2}

here comma is used to show that l value is equal to k value and l is also a postfixed increment operand

there is nothing relation with comma everything is correct in the question

- srijan