Question

What will be the value of k for x^3-3x^2+3x+k has3 as its one of zero?

Answer 1

$\huge{\mathcal{\blue{Answer}}}$

The value of k for which the cubic equation

$x {}^{3} - 3x {}^{2} + 3x + k$

has 3 as its zeroes is

$(3) {}^{3} - 3(3) {}^{2} + 3(3) + k = 0 \\ 27 - 3(9) + 9 + k = 0 \\ 27 - 24 + 9 + k = 0 \\ 9 + k = 0$

$\huge{\mathcal{\green{\boxed{k=-9}}}}$

Answer 2

Answer:

The value of k is - 9.

Step-by-step explanation:

Given:

p(x) = $x^{3}$ - $x^{2}$ + 3x + k

Checking with p(3):

p(3) = $3^{3}$ - (3)(3$)^{2}$ + 3x + k = 0 (As it is given that 3 is one of the zeroes)

=> 27 - 27 + (3) (3) + k

=> 9 + k = 0

=> k = - 9

Therefore, the value of k is - 9.