Question

What will be the value of k if the equation x^2+6x+k=6 has real and distinct roots?

Answer 1

Answer:

k > 9

Step-by-step explanation:

for a polynomial to have real and distinct roots, b²-4ac > 0

=> for the given polynomial, 6²-4(1)(k) >0

=> -4k > -36

=> k > 9

therefore, k is a real number more than 9