What will be the value of k if the equation x^2+6x+k=6 has real and distinct roots?
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Answer:
k > 9
Step-by-step explanation:
for a polynomial to have real and distinct roots, b²-4ac > 0
=> for the given polynomial, 6²-4(1)(k) >0
=> -4k > -36
=> k > 9
therefore, k is a real number more than 9
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