Question

What will be the value of molality for an aqueous solution of 10% percentage weight by weight in a o h?

Answer 1

Answer:

ask your teacher

Explanation:

Answer 2

Answer:2.778 molal

Explanation:

100% solution of aq. NaOH

10%solute of NaOH

90%water as solvent

Therefore

Moles of NaOH=10/40=1/4

This will be divided by amount of solvent in kg

ie.. 90/1000=0.09

Final answer=

0.25/0.09=2.778molal