Question

What will be the value of the third number in Pythagorean triplet (6,8, __ )?​

Answer 1

Let the number be x, which implies-

6^2+8^2=x^2

36+64=x^2

100=x^2

x=+-10

x=10

Answer 2

Given:

6,8, ?

To find:

third value=?

Solution:

Pythagorean Theorem:

$\Rightarrow a^2+b^2=c^2$

$\Rightarrow 6^2+8^2=x^2\\\Rightarrow 36+64=x^2\\\Rightarrow 100=x^2\\\Rightarrow x^2=(10)^2\\\Rightarrow x=\pm 10$

The answer is "10".