Question

what will be the value of x if a=6, b=8? x = a++ + --a + b++ + a++ + a +--b

Answer 1

Answer:

12

Explanation:

20-8.. hy aahy uza answer

Answer 2

Given:

The values of $a$ and $b$ are $a = 6$ and $b = 8$.

To find:

We need to find the value of $x$, where $x = a++ \ \ + \ \ --a \ \ + \ \ b++ \ \ + \ \ a++ \ \ + \ \ a + \ \ --b$.

Solution:

Before solving this question, we need to revise some concepts related to increment and decrement.

• Pre - increment $(++p)$: In this type of increment, before assigning the value to the variable, the value is incremented by one.

• Post - increment $(p++)$: In this type of increment, after assigning the value to the variable, the value is incremented by one.

• Pre - decrement $(--p)$: In this type of decrement, before assigning the value to the variable, the value is decremented by one.

• Post - decrement $(p--)$: In this type of decrement, after assigning the value to the variable, the value is decremented by one.

Now, consider the given expression, let that equation be (i),

$x = a++ \ \ + \ \ --a \ \ + \ \ b++ \ \ + \ \ a++ \ \ + \ \ a + \ \ --b$....... (i)

We will solve the above equation part by part.

1. Consider $a++$,

• This is post - increment case.
• So, assign the value to the variable and then increment the $a$ by one.
• So, $a++=6$.
• Now the value of $a$ is $6+1=7$.

2. Now consider $--a$,

• This is pre - decrement case.
• So, before assigning the value to the variable, the value of $a$ is decremented by one.
• Now the value of $a$ is $7-1=6$.

• So, $--a=6$.

3. Consider $b++$,

• This is post - increment case.
• So, assign the value to the variable and then increment the $b$ by one.
• So, $b++=8$.
• Now the value of $b$ is $8+1=9$.

4. Consider $a++$,

• This is post - increment case.
• So, assign the value to the variable and then increment the $a$ by one.
• So, $a++=6$.
• Now the value of $a$ is $6+1=7$.

5. Consider $a$,

• The value of $a$ is $7$.

6. Now consider $--b$,

• This is pre - decrement case.
• So, before assigning the value to the variable, the value of $b$ is decremented by one.
• Now the value of $b$ is $9-1=8$.

• So, $--b=8$.

Now, substitute all these values in equation (i).

$\Rightarrow x = a++ \ \ + \ \ --a \ \ + \ \ b++ \ \ + \ \ a++ \ \ + \ \ a + \ \ --b$

$\Rightarrow x = 6 \ \ + \ \ 6 \ \ + \ \ 8 \ \ + \ \ 6 \ \ + \ \ 7 + \ \ 8$

$\Rightarrow x =41$

Therefore, the value $x$ of is $41$.