Question

What will be the value of ‘ x’ in Pythagorean triplet (41,9,x)?

Answer 1

Answer:

40

41 to the power of 2 minus 9 to the power of 2 equal to 40 to the power of 2.

So the answer is 40

Answer 2

Answer:

Step-by-step explanation:

So in my school I have learnt that the three pythagorean triplets could be taken as 2m, $m^{2}$+1, $m^{2}$-1.

Always $m^{2}$+1 is the largest side and $m^{2}$-1 is the smallest side.

So 2m=x and $m^{2}$+1 = 41 (the largest number) and $m^{2}$-1 = 9 (the smallest number

If 2m = x, then m= $\frac{x}{2}$

If  $m^{2}$+1 = 41, then $\frac{x}{2}$^2 + 1 = $\frac{x^{2} }{4}$ + 1 = 41

                             $\frac{x^{2} }{4}$ =41 - 1 = 40

Now, we know $\frac{x^{2} }{4}$  = $m^{2}$

$m^{2}$-1 =  $\frac{x^{2} }{4}$ - 1 = 9

$\frac{x^{2} }{4}$ = 9 - 1 = 8

Sorry, I could only find until this! The person who explained before me could help you