Question

What will be the value of ' x' in Pythagorean triplet (41, 9, x)?
Please answer my question briefly
First correct response to the question will be marked brainiest

Answer 1

Answer:

40

Step-by-step explanation:

${40}^{2} = 1600$

${9}^{2} = 81$

${41 }^{2} = 1681$

${4 0| }^{2} + {9}^{2} = {41}^{2}$

Answer 2

Answer:

x=40

41^2=1681

9^2=81

40^2=1600