Question

what will be the value of X in Pythagorean triplet (6,8,x).​

Answer 1

Answer:

let base = x

pythagorean triplet

H^2 = b^2 + p^2

we know that , longest side is the hypotenuse

so here H = 8

and we have assum the base = x

so p ( perpendicular ) = 6

now it is easy to solve the ques.

so taking formulae of pythagorean triplet

H^2 = b^2 + p^2

8^2 = x2 + 6^2

64 = x2 + 36

x2 = 64 - 36

x2 = 28

x = root28