Question

What will be the value of "x" in the Pythagorean triplet (30, x , 50)​

Answer 1

Given :-

• 30 , x, 50 are the Pythagoras triplets.

Find :-

• Value of x = ?

Solution :-

By Using Pythagoras theorem

H² = P² + B²

Let, Hypotenuse (H) is 50 , Base (B) is 30 and Perpendicular (P) is x.

$\dashrightarrow\tt(50) {}^{2} = x {}^{2} + {(30)}^{2} \\\dashrightarrow \tt2500 = {x}^{2} + 900 \\ \dashrightarrow \tt \: 2500 - 900 = {x}^{2} \\ \rightarrow\tt \: 1600 = x {}^{2} \\ \rightarrow \tt \sqrt{1600} = x \\\rightarrow \tt \sqrt{40 \times 40} = x \\\dashrightarrow \large \boxed{ \green{ \tt \: x = 40}}$

The value of x is 40 ,So 30 , 40 , 50 are Pythagoras triplets