Question

what will be the values of l and ml for pz and dz square orbital??​

Answer 1

Answer:

For 2pz, the respective quantum numbers are as follows ;

From 2pz , we known that electron is present in p-orbital (l=1)——————(1)

Now, as we know that

Azimuthal quantum(l) = n-1

So, n=l+1 , where n is principal quantum no.

Therefore n=1+1= 2 - - - - - - - - from(1).

And

Magnetic quantum (m) = -l———0———+l

Therefore m= -1———0———1

Hence, m= - 1 , 0 , 1 .

Last but not least,

Spin quantum (s) = +½ and -½.

#all quantum numbers are as follows :

n >=2 , l= 1 , m= - 1 , 0 , 1 , s= +½ , - ½

Answer 2

Answer:

r = float(input("Enter the radius of the circle: "))

area = math.pi* r * r

print("%.2f" %area)