Math, asked by kritikapoor18, 1 year ago

what will be the values of p for which 4x^2-3px+9=0 has equal roots


neha9122: p ka value 2 hoga

Answers

Answered by Thatsomeone
15
Hey user

Here is your answer :-

4x^2 - 3px + 9 = 0

Here a = 4 , b = - 3p & C = 9

The given quadratic equation has equal roots so

b^2 - 4ac = 0

》( - 3p )^2 - 4 ( 4 )( 9 ) = 0

》9p^2 - 144 = 0

》( - 3p )^2 - ( 12 )^2 = 0

》( - 3p - 12 )( - 3p + 12 ) = 0

》p = - 4

Thank you .


kritikapoor18: thanks dear
Answered by YashhSingh
3

Answer:

Hey user

Here is your answer :-

4x^2 - 3px + 9 = 0

Here a = 4 , b = - 3p & C = 9

The given quadratic equation has equal roots so

b^2 - 4ac = 0

》( - 3p )^2 - 4 ( 4 )( 9 ) = 0

》9p^2 - 144 = 0

》( - 3p )^2 - ( 12 )^2 = 0

》( - 3p - 12 )( - 3p + 12 ) = 0

》p = - 4

Thank you .

Step-by-step explanation:

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