what will be the values of p for which 4x^2-3px+9=0 has equal roots
neha9122:
p ka value 2 hoga
Answers
Answered by
15
Hey user
Here is your answer :-
4x^2 - 3px + 9 = 0
Here a = 4 , b = - 3p & C = 9
The given quadratic equation has equal roots so
b^2 - 4ac = 0
》( - 3p )^2 - 4 ( 4 )( 9 ) = 0
》9p^2 - 144 = 0
》( - 3p )^2 - ( 12 )^2 = 0
》( - 3p - 12 )( - 3p + 12 ) = 0
》p = - 4
Thank you .
Here is your answer :-
4x^2 - 3px + 9 = 0
Here a = 4 , b = - 3p & C = 9
The given quadratic equation has equal roots so
b^2 - 4ac = 0
》( - 3p )^2 - 4 ( 4 )( 9 ) = 0
》9p^2 - 144 = 0
》( - 3p )^2 - ( 12 )^2 = 0
》( - 3p - 12 )( - 3p + 12 ) = 0
》p = - 4
Thank you .
Answered by
3
Answer:
Hey user
Here is your answer :-
4x^2 - 3px + 9 = 0
Here a = 4 , b = - 3p & C = 9
The given quadratic equation has equal roots so
b^2 - 4ac = 0
》( - 3p )^2 - 4 ( 4 )( 9 ) = 0
》9p^2 - 144 = 0
》( - 3p )^2 - ( 12 )^2 = 0
》( - 3p - 12 )( - 3p + 12 ) = 0
》p = - 4
Thank you .
Step-by-step explanation:
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