Question

what will be the velocity if the momentum becomes 200Ns​

Answer 1

Explanation:

Given,

F=200N

P=100m/s

By second law of Newton, change in linear momentum with respect to the time is known as Force.

F=

t

P

.

t=

F

P

=

200

100

t=0.5sec

Answer 2

The velocity if the momentum becomes $800$%.  

Explanation:

$p=mv$

kinetic energy, KE=$\frac{1}{2} mv^{2}$

$mKE=\frac{1}{2}(mv)^{2}$

$=\frac{p^{2}}{2}$

$KE=\frac{p^{2}}{2m}$

now, p is increases by $200$%,$p_{1}=3p$

$KE_{1}=\frac{(3p)^{2}}{2m}$

KE increased by $=\frac{8p^{2}}{2m}$

ΔKE%$=\frac{\frac{9p^{2}}{2m} -\frac{p^{2}}{2m} }{\frac{p^{2}}{2m} }*100$

$=800$%.