What will be the velocity of a freely falling object 2s after the fall?
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Answer:
19.6 m/s
Explanation:
Use equation of motion
- v = u + at
Where
- v = Velocity after time t
- u = Velocity when t = 0 (aka initial velocity)
- a = Acceleration of body
- t = Time after which velocity changed from u to v
It's given that the object is freely falling. It means objects' initial velocity (u) is zero.
Also, acceleration of object is due to earth's gravity. It is 9.8 m/s² downwards
v = u + at
= 0 m/s + (9.8 m/s² × 2 s)
= 19.6 m/s
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