What will be the volume change if 607.8 Joule of work is done by the system containing ideal gas ?the surrounding exerts a constant pressure of 10 atmosphere
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Answered by
4
ANSWER
Solution:- (D) 0J
In case of expansion, work is done by the system.
Now, as we know that,
W=−P
ext.
ΔV
As the gas is expanding is vaccum which has no pressure, i.e.,
p
ext.
=0
∴W=0
Hence no work is done.
From first law of thermodynamics,
ΔU=q+W
As the system is working at constant temperature, i.e., isothermally.
∴ΔU=0
Hence q=−W=0
Hence no heat is absorbed in the expansion
Answered by
0
Answer:
60.78 L
Explanation:
W= -P* ∆V
607.8 = -10 * ∆V
∆V= -60.78 L
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