Chemistry, asked by rudrasinh9606, 4 months ago

What will be the volume occupied by 22 gram of CO2 gas at STP ?​

Answers

Answered by farhafathima884840
3

Answer:

11.2 litres

Explanation:

V = 22.4 X 0.5 = 11.2 litres

Answered by riyaj0319
1

Explanation:

The molecular weigh of CO

2

is 44 g/mole.

Twenty-two grams of CO

2

at STP corresponds to

44

22

=0.5 moles.

1 mole of CO

2

=6.022×10

23

molecules.

0.5 mole of CO

2

=3.011×10

23

molecules.

1 mole of CO

2

= 3 moles of atoms whic corresponds to 3×6.022×10

23

. atoms.

0.51 mole of CO

2

= 1.5 moles of atoms whic corresponds to 1.5×6.022×10

23

. atoms.

At STP, 1 mole of any gas occupies a volume of 22.4 L.

Hence, at STP, 0.5 mole of CO

2

gas occupies a volume of 0.5×22.4=11.2 L.

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