Question

What will be the volume occupied by 22 gram of CO2 gas at STP ?​

Answer 1

Answer:

11.2 litres

Explanation:

V = 22.4 X 0.5 = 11.2 litres

Answer 2

Explanation:

The molecular weigh of CO

2

is 44 g/mole.

Twenty-two grams of CO

2

at STP corresponds to

44

22

=0.5 moles.

1 mole of CO

2

=6.022×10

23

molecules.

0.5 mole of CO

2

=3.011×10

23

molecules.

1 mole of CO

2

= 3 moles of atoms whic corresponds to 3×6.022×10

23

. atoms.

0.51 mole of CO

2

= 1.5 moles of atoms whic corresponds to 1.5×6.022×10

23

. atoms.

At STP, 1 mole of any gas occupies a volume of 22.4 L.

Hence, at STP, 0.5 mole of CO

2

gas occupies a volume of 0.5×22.4=11.2 L.