What will be the volume occupied by 2gm of hydrogen at 300K and 4 atm if at 273K and 1atm pressure the gas occupies 22.4L.
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If at S.T.P. it occupies 22.4L volume, it is an ideal gas.
- Ideal gas law, PV=nRT
- Here, n=2/2=1 mole,
T=27+273=300K,
R=0.0820L atm mol −¹ K −¹ ,
P=4 atm
V= 1×0.0820×300/4
=6.15L
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