Question

What will be the volume of 0.01 M HCl is required to completely react with 4g NaOh

Answer 1

Hope it helps you...

Answer 2

Given:

The strength of HCl = 0.01M

The mass of NaOH = 4g

To Find:

The volume of HCl required to completely react with 4g NaOH

Solution:

The reaction of HCl and NaOH is as follows:

HCl + NaOH → NaCl + H₂O

From the reaction we can infer that:

1 mole of HCl reacts with 1 mole of NaOH

or 36.5g of HCl reacts with 40g of NaOH

Using the unitary method, the mass of HCl required to react with 4g of NaOH =

$\frac{36.5X4}{40}$

= 3.65g

0.01M HCl means that 0.01 moles of HCl are present in 1000mL of solution.

or 0.365 g HCl are present in 1000mL of solution.

Again using the unitary method, the volume of the solution having 3.65g of HCl = 10000mL = 10 L

Hence, 10 L of 0.01 M HCl is required to completely react with 4g NaOH.