Question

what will be the volume of 32 gram of O2 at STP ​

Answer 1

Explanation:

given mass = 32 g

molecular mass = 16×2 = 32g

volume at stp= given mass / molecular mass × 22.4 L

= 32/32 ×22.4

= 22.4 Lvolume of 32 gram and o2 at stp = 22.4 L

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therefore,

Answer 2

Answer:

22.4L

Explanation:

1 mole of any gas at STP will contain 22.4 L

as the molecular mass of oxygen is 32G

32g of oxygen = 1 mole

so as per the equation

no of mole =given volume divided by STP

1= volume divided by 22.4L

=22.4L