What will be the volume of 8g of H, gas (H=1) at the pressure of 4 atmosphere and temperature of 300K? (R = 0-082 litre-atmosphere mol'' K ')
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Answer:
1 Answer
Nam D.
Jan 11, 2018
24.42
=
24420
c
m
3
Explanation:
We are going to use the ideal gas law, which states that
P
V
=
n
R
T
P
is pressure in pascals
(
P
a
)
V
is volume in
m
3
n
is the number of moles of the substance
R
is the gas constant
T
is the temperature in Kelvin
(
K
)
Since we are using atmospheric pressure as units and the gas constant as
0.082
L
i
t
−
a
t
m
−
m
o
l
−
1
K
−
1
, then our volume will be in liters
(
l
)
.
So, plugging in
P
=
4
a
t
m
,
n
=
8g
2.016g/mol
≈
3.97
mol
,
R
=
0.082
, and
T
=
300
K
, we get
V
=
n
R
T
P
=
3.97
⋅
0.082
⋅
300
4
≈
24.42
l
=
24420
c
m
3
of hydrogen gas
(
H
2
)
.
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