Question

What will be the volume of a cylinder whose radius is 7 cm and whose height
is double the diameter?​
​

Answer 1

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Question:-

• What will be the volume of a cylinder whose radius is 7 cm and whose height is double the diameter?

$\text{\large\underline{\red{Given:-}}}$

• Radius of cylinder is 7 cm.

$\text{\large\underline{\orange{To find :-}}}$

• Volume of cylinder.

$\text{\large\underline{\pink{Solution:-}}}$

Diameter = Radius × 2

• = 7 × 2

• = 14

Diameter of cylinder is 2

It is given that, height is double the diameter of cylinder.

So,

• $⟹$ Diameter is 14 cm

• $⟹$Height = 14 × 2

• $⟹$= 28

Height of cylinder is 28 cm.

Diagram:-

$\setlength{\unitlength}{1mm}\begin{picture}\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){1}{\sf{7 cm}}\put(9,17.5){\sf{28 cm}}\end{picture}$

Now,

Volume of cylinder is πr²h

Where,

• r is radius and h is height of cylinder.

Put r and h in formula:-

• $⟹$ 22/7 × (7)² × 28

• $⟹$ 22/7 × 7 × 7 × 28

• $⟹$ 22 × 7 × 28

• $⟹$$\boxed{\orange{\boxed{\textbf{4312}}}}$

Therefore,

$\boxed{\pink{\boxed{\textbf{Volume\:of\: cylinder\:is\:4312\:cm². }}}}$

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