Science, asked by she2tags2unapey, 1 year ago

What will be the volume of chlorine gas at S.T.P. produced during electrolysis of water molten magnesium chloridewhich produces 6.5 gram of mg

Answers

Answered by santy2
21
From the formula of magnesium chloride (MgCl2):
One mole of MgCl2 gives 1 mole of Mg (24g) and one mole of Chlorine gas (Cl2)

One mole of gas occupies 22.4 liters (22400 cm³) at S.T.P.

⇒ 24g of Mg ≡ 22400 cm³ of Chlorine gas at S.T.P.
∴ 6.5 g of Mg ≡ (22400 x 6.5) ÷ 24
                         ≡ 6066.67 cm³
Answered by bsharma23sl
0

Answer:

During electrolysis of water molten magnesium chloride (MgCl₂) which produces 6.5 grams of Mg, the volume of chlorine gas produced at S.T.P will be 5.6 L.

Explanation:

One mole of any gas at the S.T.P has a 22.4 L volume.

One mole of molten magnesium chloride (MgCl₂) produces 1 mole of Mg (24 gms) and 1 mole of Chlorine gas (22.4 L).

If 6 gms of Mg is produced, then how many liters of chlorine gas is produced.  

Calculations -

24 gms of Mg = 22.4 L of chlorine gas at S.T.P

6 gms of Mg = (22.4/24) ×  6 L = 5.6 L of chlorine gas at S.T.P

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