Question

what will be the volume of cl2 produced at stp durning electolysis of mgcl2 which produces 6.5 g mg

Answer 1

Answer:

From the formula of magnesium chloride (MgCl2):

One mole of MgCl2 gives 1 mole of Mg (24g) and one mole of Chlorine gas (Cl2)

One mole of gas occupies 22.4 liters (22400 cm³) at S.T.P.

⇒ 24g of Mg ≡ 22400 cm³ of Chlorine gas at S.T.P.

∴ 6.5 g of Mg ≡ (22400 x 6.5) ÷ 24

                         ≡ 6066.67 cm³

Answer 2

Answer:  6L

In the given electrolysis we have

moles of Mg produced is equals to moles of Cl  

2

​  

 produced

moles of Mg =  

molecularmass

givenmass

​  

=  

24

6.5

​  

=0.27

therefore moles of Cl  

2

​  

 produced = 0.27

at NTP condition volume of 1 mole of gas  = 22.4 L

hence, volume of 0.27 mole of Cl  

2

​  

 = 0.24×22.4=6L

Explanation: