what will be the volume of cl2 produced at stp durning electolysis of mgcl2 which produces 6.5 g mg
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Answered by
0
Answer:
From the formula of magnesium chloride (MgCl2):
One mole of MgCl2 gives 1 mole of Mg (24g) and one mole of Chlorine gas (Cl2)
One mole of gas occupies 22.4 liters (22400 cm³) at S.T.P.
⇒ 24g of Mg ≡ 22400 cm³ of Chlorine gas at S.T.P.
∴ 6.5 g of Mg ≡ (22400 x 6.5) ÷ 24
≡ 6066.67 cm³
Answered by
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Answer: 6L
In the given electrolysis we have
moles of Mg produced is equals to moles of Cl
2
produced
moles of Mg =
molecularmass
givenmass
=
24
6.5
=0.27
therefore moles of Cl
2
produced = 0.27
at NTP condition volume of 1 mole of gas = 22.4 L
hence, volume of 0.27 mole of Cl
2
= 0.24×22.4=6L
Explanation:
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