What will be the wavelength of a proton of momentum 6.6 × 10-² kg ms-¹ .
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The de Broglie equations relate the wavelength λ to the momentum p, and frequency f to the total energy E of a particle: where h is Planck's constant.
The de Broglie equations relate the wavelength λ to the momentum p, and frequency f to the total energy E of a particle: where h is Planck's constant. λ=
mv
h
where,
m= mass=6.62∗10
−26
Kg
h= Planck's constant=6.62∗10
−34
m
2
/Kg.s
v= velocity of particle=1000m/s
λ=
1000×6.62×10
−32
6.62×10
−34
=10
−5
m
Hope it helps di
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