Question

what will be the weight of oxygen combining with 14 gram nitrogen in No n2o 3 respectively​

Answer 1

Answer:

Equation:

2 N2 + 3 O2 = 2 N2O3

2molecules of nitrogen combine with 6 atoms of oxygen  

Molar mass N2 = 28g/mol

14g = 0.5 mol N2

80% reacts = 80/100*0.5 = 0.4mol N2

1mol N2 = 6.022*10^23 molecules

0.4 mol N2 = 0.4*6.022*10^23 = 2.41*10^23 molecules

This will react with (2.41*10^23)* 6/2 = 7.23*10^23 atoms of oxygen.

Explanation:

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Answer 2

Explanation:

N2 + 3/2 O2 ------> N2O3

28 g N2------> 48 g O2

14 g N2 ------> 48 * 14 / 28 => 24 g

I hope it will be helpful for you.

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