Physics, asked by sasvisan, 11 months ago

what will be the work done in increasing the radius of soap bubble from r/2 to 2r,if surface tension of soap solution is T​

Answers

Answered by poonambhatt213
27

Answer:

Explanation:

=> Surface energy of soap bubble :

U = T * 4πr²

U₁ = T * 4π(r/2)² = T * 4π(r²/4) = πTr²

U₂ = T * 4π(2r)² = 16πTr²

=> The work done in increasing the radius of soap bubble is equal to the increase in surface energy.

∴W = (U₂ - U₁)

= 16πTr² - πTr²

= 15πTr²

Thus, the work done in increasing the radius of soap bubble will be 15πTr².

Answered by CᴀɴᴅʏCʀᴜsʜ
11

Answer:Surface energy of soap bubble :

U = T * 4πr²

U₁ = T * 4π(r/2)² = T * 4π(r²/4) = πTr²

U₂ = T * 4π(2r)² = 16πTr²

=> The work done in increasing the radius of soap bubble is equal to the increase in surface energy.

∴W = (U₂ - U₁)

= 16πTr² - πTr²

= 15πTr²

Thus, the work done in increasing the radius of soap bubble will be 15πTr².

Explanation:

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