Question

What will be the work done when 1 mole of gas expands isothermally from 15 litre to 50 lire against a constant pressure of 1 atm at 25 degree celcius??

Answer 1

$work \: done \\ = - p(v2 - v1) \\ = - 1 \times( 50 - 15) \\ 35 \times - 1 = - 35l \: atm$

Answer 2

Answer:Work done by the gas 35 kilo joules.

Explanation;

A gas is expanding isothermally on constant pressure of  1 atm.

Initial volume = 15 L=$V_1$

Final volume = 50 L=$V_2$

Work done by the gas :

$w=-p_{opp}(V_2-V_1)=1 atm\times (50 L- 15 L)= 1 atm \times 35 L=-35 kJ$

Work done by the gas 35 kilo joules.