What will be the work done, when a body of mass 100 kg moves uniformly on a frictionless surface through
a distance of 5 m?
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Answer:
Given Mass of the object m=50kg and displacement s=100m.
Now frictional force f=μN where μ=coefficient of friction and N= normal force
We know N=mg; where g=acceleration due to gravity =10 m/s
2
N=50×10=500N.
Thus frictional forcef=500μ
Again work done by frictional forceW
f
=fscosθ where s= displacement =100 m and θ=0
0
ThereforeW
f
=500μ×100=50μkJ
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