Question

what will be the work function of a substance for a threshold frequency of 43.9 ×10¹³ Hz .??​

Answer 1

Answer:

The work function of a substance for a threshold frequency of 43.9 × 10¹³ Hz is 280.618 × 10⁻²¹J.

Explanation:

According to the question,

↣  Threshold frequency = 43.9 × 10¹³Hz

We’ll have to find the work function of the substance.

For this, we’ll use the formula :

↣  E = hv₀

Wherein :

↣  E = Work function

↣  h = Planck’s constant : 6.62 × 10⁻³⁴

↣  v₀ = Threshold frequency : 43.9 × 10¹³

Now, let’s substitute the values and solve for E :

↣  E = hv₀

↣  E = (6.62 × 10⁻³⁴ JHz⁻¹) × (43.9 × 10¹³)

↣  E = 6.62 × 43.9 × 10⁻³⁴ × 10¹³

↣  E = 290.618 × 10⁽⁻³⁴⁺¹³⁾

↣  E = 290.618 × 10⁻²¹J

Therefore, the work function of the substance is 290.618 × 10-²¹J.