Question

What will be value of force of 10 N in a new system with units as M = 500 g L = 10 cm. T = 1 minute? 216000 new unit 360000 new unit 400000 new unit 720000 new unit these are options tell correct

Answer 1

Answer:

Explanation:

Using dimensional analysis,

The dimensions will remain same for Force

Therefore,$10*[M_{1} ^1L_{1} ^1T_{1} ^-^2]=X[M_{2} ^1L_{2} ^1T_{2} ^-^2]$,

(subscript 1 values are in MKS system and subscript 2 values are the given new values)

Now,$X=10*[(\frac{M_{1} }{M_{2} })^1(\frac{L_{1} }{L_2})^1(\frac{T_{1}}{T_{2} })^-^2]$

Putting values,$X=10*[(\frac{1000g}{500g} )(\frac{100cm}{10cm})(\frac{1sec}{60sec})^-^2]$

(I have converted the MKS values so as to calculate easily)

Therefore,$X=10*[(2)*(10)*(3600)]$

$X=200*3600=720000$ new unit

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