Question

what will be weight od ritu, if her mass on earth is 40kg ?
​

Answer 1

Explanation:

Sold to the first customer

\begin{gathered}\frac{x}{2} + \frac{1}{2} = \frac{x + 1}{2} \\\end{gathered}

2

x

+

2

1

=

2

x+1

Remaining stock

\begin{gathered}= x - \frac{x + 1}{2} = \frac{2x - x - 1}{2} \\ = \frac{x - 1}{2}\end{gathered}

=x−

2

x+1

=

2

2x−x−1

=

2

x−1

Sold to the second customer

\begin{gathered}= \frac{1}{2} \times \frac{x - 1}{2} + \frac{1}{2} \\ = \frac{x - 1}{4} + \frac{1}{2}\end{gathered}

=

2

1

×

2

x−1

+

2

1

=

4

x−1

+

2

1

= \frac{x - 1 + 2}{4} = \frac{x + 1}{4}=

4

x−1+2

=

4

x+1

Remaining stock

\begin{gathered}= ( \frac{x - 1}{2}) - ( \frac{x + 1}{4} ) \\ = \frac{2x - 2 - x - 1}{4} \\ = \frac{x - 3}{4}\end{gathered}

=(

2

x−1

)−(

4

x+1

)

=

4

2x−2−x−1

=

4

x−3

Sold to the third customer

\begin{gathered}= \frac{1}{2} \times \frac{x - 3}{4} + \frac{1}{2} \\ = \frac{x - 3 + 4}{8} \\ = \frac{x + 1}{8}\end{gathered}

=

2

1

×

4

x−3

+

2

1

=

8

x−3+4

=

8

x+1

Remaining stock

\begin{gathered}= ( \frac{x - 3}{4} ) - ( \frac{x + 1}{8} ) \\ = \frac{2x - 6 - x - 1}{8} = \frac{x - 7}{8}\end{gathered}

=(

4

x−3

)−(

8

x+1

)

=

8

2x−6−x−1

=

8

x−7

Sold to the fourth customer

\begin{gathered}= \frac{1}{2} \times \frac{x - 7}{16} + \frac{1}{2} \\ = \frac{x - 7}{16} + \frac{1}{2} \\ = \frac{x - 7 + 8}{16} \\ = \frac{x + 1}{16}\end{gathered}

=

2

1

×

16

x−7

+

2

1

=

16

x−7

+

2

1

=

16

x−7+8

=

16

x+1

Therefore,

\begin{gathered}x - ( \frac{x + 1}{2} + \frac{x + 1}{4} + \frac{x + 1}{8} + \frac{x + 1}{16} ) \\ = 15\end{gathered}

x−(

2

x+1

+

4

x+1

+

8

x+1

+

16

x+1

)

=15

\begin{gathered}= > x - ( \frac{8x + 8 + 4x + 4 + 2x + 2 + x + 1}{16} ) \\ = 15\end{gathered}

=>x−(

16

8x+8+4x+4+2x+2+x+1

)

=15

\begin{gathered}= > x - ( \frac{15x + 15}{16} ) = 15 \\ = > \frac{16 x - 15x - 15}{16} \\ = 15 \\ = > x - 15 = 16 \times 15 = 240 \\ = > x = 240 + 15 = 255.\end{gathered}

=>x−(

16

15x+15

)=15

=>

16

16x−15x−15

=15

=>x−15=16×15=240

=>x=240+15=255.

Answer 2

$\; \star \; {\underline{\boxed{\pmb{\orange{\frak{ \; Given\; :- }}}}}}$

➺ Mass of a body is 40 kg.

$\star \;{\underline{\boxed{\pmb{\red{\frak{ \; To \; Find \; :- }}}}}}$

➺ Weight = ?

$\; \star \; {\underline{\boxed{\pmb{\purple{\frak{ \; SolutioN \; :- }}}}}}$

$❒{\underline{\underline{\sf{ \; Calculating \: weight \;  \: : - }}}}$

${\underline{\underline{\sf{ \; Formula \; Used \; :- }}}}$

${ \underline{ \boxed{\sf{Weight =Mass×Gravitational \:Acceleration }}}}$

${\longrightarrow \; {\sf{Weight=Mass×Gravitational Acceleration }}} \;$

${\longrightarrow \; {\sf{Weight = 40 \times 9.8 }}} \;$

${\longrightarrow \;{\sf{Weight = 40 \times \dfrac{98}{10} }}} \;$

${\longrightarrow \;{\sf{Weight=4\cancel0\times \dfrac{98}{ \cancel{10}} }}} \;$

${\longrightarrow \; {\sf{Weight = 4 \times 98}}} \;$

${\; \longrightarrow \; {{ \pink{ \underline{ \boxed{ \frak{ Weight=392N}}}}}} }\;\red\bigstar$

$\begin{gathered} \\ \\ \end{gathered}$

$\therefore$Weight of the body is 392 N

$\begin{gathered}\begin{gathered}\begin{gathered} \\ {\underline{\rule{300pt}{9pt}}} \end{gathered} \end{gathered}\end{gathered}$