Question

What will be work-done in charging 20uF capacitor to 500 volt ?​

Answer 1

Answer:

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Answer 2

Workdone is 5 J

Explanation:

Given,

Capacitance, C = 20$\mu$ f

Potential difference , V = 500 volt

Charge stored, = Q

C = $\frac{Q}{V}$

So that,

Q = CV

W = QV

W = $CV\times V$

W = $C\times V^2$

W = $20\times 10^{-6} \times 500^2$

W = 5 J

Workdone is 5 J