Question

What will be work done required to stop a car of mass 1500 kg moving with velocity 72Km/h​

Answer 1

Explanation:

Given data,

u=72 km/h=20m/s

m=1500kg

v=0 m/s

Work done=change in kinetic energy

=final kinetic energy - initial kinetic energy

=0 - 1/2mv

=-1/2*1500*20*20

=750*400

-3,00,000 jule

PLEASE MARK ME AS BRAINLIEST

Answer 2

Answer :

⇒Velocity->72km/h...... ⇒KE=1/2×15000×(72)²....... ... ⇒KE=3888×10×10³J........ So work require will be 3888×10×10³J.......!!