Question

what will get printed a=1,b=-5 and c=6
A) Roots are real and are -2 and -3
B) Roots are real and are 2 and 3
C)Roots are imaginary and cannot be calculated.
D)Roots are real and equal and are 5​

Answer 1

Answer:

B) Roots are real and are 2 and 3

Explanation:

x = -b ± √b²-4ac / 2a

x = -(-5) ± √(-5)²-4(1)(6) / 2

x = 5 ± √25-24 / 2

x = 5 ± √1 / 2

x = 5+1/2, 5-1/2

x = 6/2, 4/2

x = 3, 2

Answer 2

Answer:

The correct answer is option B) Roots are real and are 2 and 3.

Explanation:

We know that the quadratic formula gives us the roots as:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where $b^2-4ac$ is the discriminant.

Here, we are given: $a=1$, $b=-5$ and $c=6$.

First finding the discriminant, we get:

$b^2-4ac=(-5)^2-4(1)(6)$

or we can say:

$b^2-4ac=25-24$

$b^2-4ac=1$

Now, substituting the information in quadratic formula, we get:

$x=\frac{-(-5)\pm\sqrt{1}}{2(1)}$

Simplifying it, we get:

$x=\frac{5\pm1}{2}$

or we can say:

$x=\frac{5+1}{2},\frac{5-1}{2}$

$x=\frac{6}{2},\frac{4}{2}$

which gives us:

$x=3,2$

Option b) is the correct answer.