What will Happen if NaOH is used in place of dil. sulphuric acid and
(i) It will produce sodium zincate (salt) and hydrogen gas.
(ii) It will produce sodium sulphate and hydrogen gas.
(iii) It will produce sodium zincate (salt) and carbon dioxide gas.
(iv) It will produce sodium sulphate and carbon dioxide gas.
Answers
Answer:
(i) sodium zincate and hydrogen gas
Explanation:
acids like sulphuric acid mentioned above react with Metals to form salt + hydrogen gas
BUT
in case of bases only NaOH & KOH react with only 2 metals specifically Zn & Al to form salt and hydrogen gas
Since in q its NaOH + Zn ---> Na2ZnO2 + H2 is formed
Answer:
The correct answer is (i) It will produce sodium zincate (salt) and hydrogen gas.
Explanation:
When sodium hydroxide is used instead of dilute sulphuric acid and the tube is heated, sodium zincate and hydrogen gas are formed. However, heating the test tube increases the rate of hydrogen gas formation in the same way that heating the reaction mixture increases the rate of reaction.
Zn + 2NaOH ⇨ Na₂ZnO₂ + H₂
Properties of sodium zincate:
- It is an inorganic substance.
- Odorless
- The zinc value in sodium zincate is +2.
- It is slightly soluble in water and insoluble in alcohol.
When soluble in water, it forms aqueous ions. The dissociation reaction of sodium zincate is as follows;
2Na₂Zn(OH)₄ 4Na+2ZnO₂- +4OH-
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