Question

what will happen if two terminal of capacitor are shorted? how capacity of capacitor varies with dielectric media?​

Answer 1

Answer:

When two terminals are shorted then capacitance of the capacitor becomes ZERO

When dielectric is introduced between the plates of capacitor then it's capacitance will increase

Explanation:

As we know that charge stored between the plates of capacitor is given as

$Q = CV$

so here we know that

C = capacitance of the capacitor

V = voltage difference between the plates of capacitor

Now if we short the two plates of capacitor then voltage difference between the plates of capacitor is V = 0

so we will have

$Q = 0$

so in that case capacitor will not store any charge on it

Now we know that capacitance of parallel late capacitor is given as

$C = \frac{\epsilon_0 A}{d}$

If dielectric is introduced between the plates of capacitor then its capacitance is given as

$C_{med} = \frac{k\epsilon_0A}{d}$

so capacitance is increased by "k" times

#Learn

Topic : Capacitance

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